成人快手

Describing motion - AQAMotion in a straight line

The movement of objects can be described using motion graphs and numerical values. These are both used to help in the design of faster and more efficient vehicles.

Part of Physics (Single Science)Forces

Motion in a straight line

Speed, distance and time

is how far an object moves. It does not include an associated direction, so distance is a quantity.

is the of distance - it is the distance travelled per unit time. Like distance, speed does not have an associated direction, so it is a scalar quantity.

Learn more on displacement, distance and speed in this podcast

Typical speeds

When people walk, run, or travel in a car, their speed will change. They may speed up, slow down or pause for traffic. The speed at which a person can walk, run or cycle depends on many factors including:

  • age
  • terrain
  • fitness
  • distance travelled

Some typical values for speed in metres per second (m/s) include:

Method of travelTypical speed (m/s)
walking1.5
running3
cycling6
car13-30
train50
aeroplane250
Method of travelwalking
Typical speed (m/s)1.5
Method of travelrunning
Typical speed (m/s)3
Method of travelcycling
Typical speed (m/s)6
Method of travelcar
Typical speed (m/s)13-30
Method of traveltrain
Typical speed (m/s)50
Method of travelaeroplane
Typical speed (m/s)250

It is not only moving objects whose speed can vary. The speed of the wind and the speed of sound also vary. A typical value for the speed of sound in air is about 330 m/s.

Calculations involving speed, distance and time

The distance travelled by an object moving at constant speed can be calculated using the equation:

distance travelled = speed 脳 time

\(s = v~t\)

This is when:

  • distance travelled (s) is measured in metres (m)
  • speed (v) is measured in metres per second (m/s)
  • time (t) is measured in seconds (s)

Example

A car travels 500 m in 50 s, then 1,500 m in 75 s. Calculate its average speed for the whole journey.

First calculate total distance travelled (s):

500 + 1,500 = 2,000 m

Then calculate total time taken (t):

50 + 75 = 125 s

Then rearrange \(s = v~t\) to find v:

\(v = \frac{s}{t}\)

\(v = 2,000 \div 125\)

\(v = 16~m/s\)