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Solving 'number' problems - OCRNumber problems - percentages and fractions

Number problems often involve a combination of fractions, decimals, percentages and ratio. They can be set in a real-life context. A framework can be used to tackle these problems.

Part of MathsProblem solving

Number problems - percentages and fractions

Example 2

Jars of sweets (A and B)

Mrs Brown has two jars of sweets. The jars contain the same number of sweets in total.

  • 25% of the sweets in Jar A are mint.
  • Two fifths of the sweets in Jar B are mint.

There are 10 mint sweets in Jar A, how many mint sweets are there in Jar B?

1. What do I have to do?

Read the question through twice. Highlight or underline the important pieces of information in the question.

2. What information do I need?

The most important parts of this question are 25% of the sweets in Jar A are mint and two fifths of Jar B are mint. It is clear this question is going to involve using fractions and percentages.

The question asks how many mints are in jar B. The answer needs to be a number rather than a percentage or fraction.

Two fifths is equivalent to \(\frac{4}{10}\) = 40%, which is greater than 25% so there are more sweets in Jar B.

3. What information don鈥檛 I need?

Everything in this question is relevant to working out the answer.

4. What maths can I do?

The most important parts of this question are 25% of the sweets in Jar A are mint and two fifths of those in Jar B are mint. This provides the way into the question.

Step A

Look at the information given.

There are 10 mint sweets in Jar A.

25% of the sweets in Jar A are mint ones.

Therefore 25% of Jar A must be 10 mint sweets.

Step B

Now find the number of sweets in Jar A.

The total number of sweets in Jar A is 100%.

If 25% is 10 sweets, 100% is four times 25% therefore there must be \(10 \times 4 = 40\) sweets in Jar A.

Step C

Now find the number of mint sweets in Jar B.

There is the same number of sweets in each jar.

Therefore Jar B must also contain 40 sweets.

Two fifths of Jar B are mint sweets therefore \(\frac{2}{5}\) of 40 needs to be found.

Firstly find \(\frac{1}{5}\) of 40 by dividing by 5.

\(40 \div 5 = 8\)

Now find two fifths by multiplying your answer by 2.

\(8 \times 2 = 16\)

There are therefore 16 mint sweets in Jar B.

5. Is my solution correct?

It is important to check any calculations at the end, even if a calculator was used.

There should be more mint sweets in Jar B than Jar A, which there is.

6. Have I completed everything?

The answer is supposed to be a whole number of sweets, which it is.

Nothing else was asked for.