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Dimensional analysis - Intermediate & Higher tier - WJECLength, area and volume: multiplying and dividing

Dimensional analysis allows us to make inferences and deductions about formulae. It provides us with an alternative way to check our own calculations and those of others.

Part of Maths Numeracy (WJEC)Geometry and Measure

Length, area and volume: multiplying and dividing

The volume of a cylinder is calculated by the equation \(\text \pi {r}^{2}{h}\). This equation involves multiplying three lengths together

A cylinder with radius labelled 'r' and height labelled 'h'

Multiplying or dividing quantities with units often occurs in everyday life. To calculate the area of a room (for the purposes of fitting a carpet, for example) you would need to multiply the length of the room by the width of a room.

Let鈥檚 look a little more closely at this:

\({length}~(m)~\times~{width}~(m)~=~{area}~{(m^2)}\)

The unit \({m^2}\) is different to \({m}\). So what we have found is that multiplying two units results in an answer in a different unit. Also, as length is one dimensional, when you multiply two one dimensional quantities together, you get a two dimensional quantity.

You should know the following in preparation for your exam:

  • Number 脳 Length = Length (one dimension)
  • Number 脳 Area = Area (two dimensions)
  • Number 脳 Volume = Volume (three dimensions)
  • Length 脳 Length = Area (two dimensions)
  • Length 脳 Length 脳 Length = Volume (three dimensions)
  • Length 脳 Area = Volume (three dimensions)

The opposite is also true:

Area 梅 Length = Length

Volume 梅 Number = Volume

Question

The letters \({a}\) and \({b}\) both represent lengths.

Does the following calculation make sense, and if it does, how many dimensions does the answer have?

\({a}~\times~{b^2}\)

Question

The letters \({a}\), \({b}\) and \({c}\) all represent lengths.

Does the following calculation make sense, and if it does, how many dimensions does the answer have?

4\({c}~+~{a^2}\)

Question

The letters \({a}\), \({b}\) and \({c}\) all represent lengths.

Does the following calculation make sense, and if it does, how many dimensions does the answer have?

\(\frac {a^2} {b}~+\)4\({c}\)