成人快手

Antenatal and postnatal screeningAutosomal dominant inheritance

Antenatal and postnatal screening are used to protect the health of mothers and babies. Antenatal techniques include ultrasound imaging, dating scans, blood and urine tests and diagnostic testing, such as amniocentesis, CVS and genetic screening. Postnatal screening can involve diagnostic testing such as PKU.

Part of Human BiologyPhysiology and Health

Single gene disorders - Autosomal dominant inheritance

Any sufferers from autosomal dominant conditions only require one dominant allele so can be either homozygous dominant or heterozygous. This affects both genders equally.

An example of an autosomal dominant inherited diseases is .

Huntington鈥檚 disease is an inherited disorder that causes damage to certain brain cells. It is caused by a . In a genetic diagram:

  • the can be shown as h
  • the dominant allele can be shown as H

Someone who is homozygous (HH) or heterozygous (Hh) for the dominant allele will develop Huntington鈥檚 disease.

In example 1, the mother carries one copy of the Huntington鈥檚 allele and has the disease. The father does not carry the Huntington鈥檚 allele, so he does not have the disease. The chance of them producing a child with Huntington鈥檚 disease is 2 in 4, or 50%.

The Mother has one copy of the allele for Huntington's Disorder, the father has none. Therefore there's a 50% chance their offspring will have Huntington's Disorder.
Figure caption,
Example 1

In example 2, both parents have one dominant allele and one recessive allele. This means that they are for that particular gene. The chance of them producing a child with Huntington鈥檚 disease is 3 in 4, or 75%.

Mother and Father both carry the allele for Huntington's Disorder so both have the disorder.  Therefore there's a three in four chance their offspring will have Huntington's Disorder.
Figure caption,
Example 2

In example 3, the mother is heterozygous. The father is because he has two identical alleles for that particular gene. The chance of them producing a child with Huntington鈥檚 disease is 4 in 4, or 100%.

Half the possible offspring will be homozygous, HH, and half will be heterozygous, Hh. The ratio of HH to Hh is 1:1 or 50%.

The mother has one copy of the Huntington's allele, the father has two.  Therefore there's a 100% chance any children will have it.
Figure caption,
Example 3