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Sector, segment and arc - Higher only – WJECLength of an arc

Sometimes we need to know how to calculate values for specific sections of a circle. These can include arc lengths, the area and perimeter of sectors and the area of segments.

Part of MathsGeometry and Measure

Length of an arc

We can find the length of an arc by using the formula:

\(\frac{\texttheta}{360} \times \pi~\text{d}\)

\(\texttheta\) is the angle of the sector and \(\text{d}\) is the diameter of the circle.

Example

A sector with an angle of 80° and a radius of 12 cm.

This sector has a minor arc, because the angle is less than 180⁰.

We are given the radius of the sector so we need to double this to find the diameter.

Here, \(\text{d}\) = 24 and \(\texttheta\) = 80⁰.

Substituting these values into the formula, we get:

\(\text{Arc length =}~\frac{80}{360} \times \pi \times {24}\)

\(\text{= 16.755...}\)

\(\text{= 16.8 cm (to one decimal place)}\)

Question

Find the length of the minor arc AB.

A sector with an angle of 60° and a radius of 7.3 cm.

Example

A sector with an angle of 210° and a radius of 60 mm.

This sector contains a major arc, because the angle is greater than 180⁰.

We still follow the same process for this question. Don’t forget to double the radius to get the diameter.

\(\text{Arc length =}~\frac{210}{360} \times \pi \times {120}\)

\(\text{= 219.91...}\)

\(\text{= 219.9 mm (to one decimal place)}\)

Question

Find the length of the major arc AB.

A sector with an angle of 330° and a radius of 4.60 cm.