Sometimes we need to know how to calculate values for specific sections of a circle. These can include arc lengths, the area and perimeter of sectors and the area of segments.
Part of MathsGeometry and Measure
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We can find the length of an arc by using the formula:
\(\frac{\texttheta}{360} \times \pi~\text{d}\)
\(\texttheta\) is the angle of the sector and \(\text{d}\) is the diameter of the circle.
This sector has a minor arc, because the angle is less than 180⁰.
We are given the radius of the sector so we need to double this to find the diameter.
Here, \(\text{d}\) = 24 and \(\texttheta\) = 80⁰.
Substituting these values into the formula, we get:
\(\text{Arc length =}~\frac{80}{360} \times \pi \times {24}\)
\(\text{= 16.755...}\)
\(\text{= 16.8 cm (to one decimal place)}\)
Find the length of the minor arc AB.
\(\text{Arc length =}~\frac{60}{360} \times \pi \times {14.6}\)
\(\text{= 7.644...}\)
\(\text{= 7.6 cm (to one decimal place)}\)
This sector contains a major arc, because the angle is greater than 180⁰.
We still follow the same process for this question. Don’t forget to double the radius to get the diameter.
\(\text{Arc length =}~\frac{210}{360} \times \pi \times {120}\)
\(\text{= 219.91...}\)
\(\text{= 219.9 mm (to one decimal place)}\)
Find the length of the major arc AB.
\(\text{Arc length =}~\frac{330}{360} \times \pi \times {9.2}\)
\(\text{= 26.49...}\)
\(\text{= 26.5 cm (to one decimal place)}\)